arrays - printing an string in cross manner using c program -

i'am trying write program converting given string in cross manner(i.e diagonal left-right , right-left). if string length returns message else arrange in cross form.

the code is:

#include<stdio.h> #include<string.h>  int main() {         char str[50];     char str2[50][50];     int lenstr;     int i,j;     char temp;      printf("enter string :\n");     scanf("%s",str);     lenstr = strlen(str);     if(lenstr %2 == 0)     {         printf("the string length must odd length");      }      else     {         j = 0;         temp = 0;          for(i = 0;i == lenstr;i++)         {               str2[i][j] = str[i];               j = j + 1;         }          for(i = lenstr; i==0 ;i--)         {               j = lenstr;               str2[i][j] =  str[temp];               temp = temp + 1;               j = j - 1;          }          for(i = 0;i<lenstr;i++)         {               for(j = 0;j<lenstr;j++)              {                   printf("%c",str2[i][j]);              }               printf("\n");            }       }       return 0;  } 

the output program must example: geeks

g       g   e   e     e    k   k  s       s 

but output obtained consists of different shapes(like heart,smiley face etc...). explain concept behind correct , if can please explain when using pointers same program. appreciated.

in code, need change for loop condition checking expressions, i == lenstr , later i==0. not entering loop, essentially.

instead, can replace whole block

for(i = 0;i == lenstr;i++)   {       str2[i][j] = str[i];       j = j + 1;   }    for(i = lenstr; i==0 ;i--)   {       j = lenstr;       str2[i][j] =  str[temp];       temp = temp + 1;       j = j - 1;    } 

in code by

for(i = 0;i<lenstr;i++)     for(j = 0;j<lenstr;j++)       str2[i][j] = ' ';      //fill 2d array space    for(i = 0;i < lenstr;i++)   {       str2[i][i] = str[i];               //set character       str2[i][lenstr- -1] = str[i];    //reverse position   } 

and desired output.

see live.