regex - grep first n rows, return file name only -

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i can following search need , return file name: grep -l "mysearchstring" ./*.xml files searching huge takes forever. string searching appear in first 200 rows how can search first 200 rows , still return file name?

you can do:

for file in *.xml;    head -200 "$file" | grep -q "mysearchstring" && echo "$file" done

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