Sorting XML file by element -

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i want sort xml file elements in same level alphabetically. means, sorting elements on first level, inside every element subelement , on recursively. must multilevel, not 1 level (that solved in other question). example (please ignore content , meaning):

<example>     <note>         <to>tove</to>         <from>jani</from>         <heading>reminder</heading>             <headb>head</head3>             <heada>head</head3>         <body>don't forget me weekend!</body>     </note>     <next>         <c>blabla</c>         <a>blabla</a>     </next> </example>

to:

<example>     <next>         <a>blabla</a>         <c>blabla</c>     </next>     <note>         <body>don't forget me weekend!</body>         <from>jani</from>         <heading>reminder</heading>             <heada>head</head3>             <headb>head</head3>         <to>tove</to>     </note> </example>

the xml can contain thousands of lines , many levels of elements

you should able use identity transform , add xsl:sort sort on either name() or local-name().

example...

xml input (well formed , more complicated original.)

<example>     <note>         <to>tove</to>         <from>jani</from>         <heading>reminder</heading>         <headb>head</headb>         <heada>head</heada>         <body>don't forget me weekend!</body>     </note>     <next>         <c>blabla</c>         <a>blabla</a>     </next>     <djh>         <!-- comment -->         <foo attr="test">             <bar>                 <baz>text</baz>                 <foo><!--comment--></foo>             </bar>             <baz attr="test">                 <foo/>                 <bar/>             </baz>         </foo>         <?pi?>         <baz>             <bar>                 <foo/>                 <baz/>             </bar>             <foo>                 <bar/>                 <baz/>             </foo>         </baz>     </djh> </example>

xslt 1.0

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform">     <xsl:output indent="yes"/>     <xsl:strip-space elements="*"/>      <xsl:template match="@*|node()">         <xsl:copy>             <xsl:apply-templates select="@*|node()">                 <xsl:sort select="local-name()"/>             </xsl:apply-templates>         </xsl:copy>     </xsl:template>  </xsl:stylesheet>

xml output

<example>    <djh><!-- comment --><?pi?>       <baz>          <bar>             <baz/>             <foo/>          </bar>          <foo>             <bar/>             <baz/>          </foo>       </baz>       <foo attr="test">          <bar>             <baz>text</baz>             <foo><!--comment--></foo>          </bar>          <baz attr="test">             <bar/>             <foo/>          </baz>       </foo>    </djh>    <next>       <a>blabla</a>       <c>blabla</c>    </next>    <note>       <body>don't forget me weekend!</body>       <from>jani</from>       <heada>head</heada>       <headb>head</headb>       <heading>reminder</heading>       <to>tove</to>    </note> </example>

notice though comments , processing instructions end floating top of sort order.

also note if have mixed content (element , text nodes in same parent), might want skip sorting of element. otherwise text come first in sort order (like comments , processing instructions).

here's way skip mixed content elements (comment , processing instruction output change may want experiment):

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform">     <xsl:output indent="yes"/>     <xsl:strip-space elements="*"/>      <xsl:template match="@*|node()">         <xsl:copy>             <xsl:apply-templates select="@*|node()"/>                     </xsl:copy>     </xsl:template>      <xsl:template match="*[not(text())]">         <xsl:copy>             <xsl:apply-templates select="@*|node()">                 <xsl:sort select="local-name()"/>             </xsl:apply-templates>         </xsl:copy>     </xsl:template>  </xsl:stylesheet>

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