java - simple android calculator returning too many zeros and wrong decimal point -

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so output "h" in gives me long of number decimal point in wrong spot, otherwise whole number correct. example:

333433.33333 gets displayed 333.43 should displayed

i suspect culprint 

    `h = (double) math.round(h * 100000) / 100000;`

but when change h = (double) math.round(h * 1000) / 1000; doesn't seem help.

public class dofcalculator extends fragment {  edittext txtf; spinner aspinner, cspinner;  @override public view oncreateview(layoutinflater inflater, viewgroup container,                          bundle savedinstancestate) {     view rootview = inflater.inflate(r.layout.calculators_fragment_dof, container, false);       button button = (button) rootview.findviewbyid(r.id.btn_cal);     aspinner = (spinner) rootview.findviewbyid(r.id.aspinner);     txtf = (edittext) rootview.findviewbyid(r.id.focal_length);     cspinner = (spinner) rootview.findviewbyid(r.id.coc);     final textview txtanswer = (textview) rootview.findviewbyid(r.id.txt_h);        button.setonclicklistener(new onclicklistener() {         @override         public void onclick(view v) {             string f = txtf.gettext().tostring();             string = aspinner.getselecteditem().tostring();             string c = cspinner.getselecteditem().tostring();             if (!f.isempty() ) {                 txtanswer.settext("h = " + calcullate_h(f, a, c) + "");             } else {                 toast.maketext(getactivity(), "all data required", toast.length_long).show();             }         }     });       return rootview; }  private double calcullate_h(string txtf, string txta, string txtc) {     double f = double.parsedouble(txtf.tostring());     double = double.parsedouble(txta.tostring());     double c = double.parsedouble(txtc.tostring());     double h = ((f * f) / (a * c)) + f;     h = (double) math.round(h * 100000) / 100000;     return h; }   }

from understand, h off factor of 1000, , textview showing many decimal points. recommend:

1) divide h 1000 in calculate_h. (i.e., return h / 1000)

2) use string.format show desired number of digits after decimal point. example, txtanswer.settext(string.format("h = %.2f", calculate_h(f, a, c))) show 2 digits after decimal point.


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