rdf - range function in sparql -

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i need years in given range values in sparql (especially sesame implementation).

is there way "generate" new numbers in sparql like:

select (range(2,10) ?numbers) where{}

without taking deeper look, 1 naive answer in spirit of rdf materialize numbers , use filter range. in other words, insert them graph:

  ex:year ex:anumber "1900"^^xsd:integer .   ex:year ex:anumber "1901"^^xsd:integer .   ...     ex:year ex:anumber "2100"^^xsd:integer .

and have pattern in section:

  select ?number   {       ex:year ex:number ?number .       filter (?number < 2020)       filter (?number > 1999)   }

as commented above, hard imagine use case "knowing" numbers: cross-product else in query, unless getting numbers purpose of query or filtering being applied (in latter case there no need generate numbers @ all).


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