how to replace pairwise characters in a string using Python -

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suppose have string :

x="aaaabbabaabccabbca"

and have following information :

aaa=1 abb= ignore/remove final output aba=2 abc=3 cab=4 bca= ignore/remove final output

so when translate x output y should be: y=1234

i tried:

def fun(x):     x=x.replace("aaa","1")      x=x.replace("aba","2")     x=x.replace("abb","")     x=x.replace("abc","3")     x=x.replace("bca","")     x=x.replace("cab","4")     print x

but giving me wrong answer: 123cca

i tried:

def fun(x):     z=[]         in range(0,(len(x)+1)):             if i=="aaa":                 i=i.replace("aaa",1)         z.append(i)         elif i=="aba":             i=i.replace("aba",2)     elif i=="abb":             i=i.replace("abb","")     elif i=="abc":             i=i.replace("abc",3)     elif i=="bca":             i=i.replace("bca","")     elif i=="cab":             i=i.replace("cab","4")         z.append(i)     print ",".join(z)

but there wrong syntax.

so main problem check string beginning , replace characters. please me.

thanks

here's solution print 1234 when run on string :

x = "aaaabbabaabccabbca" newstr = '' in range(0,len(x),3):     part = x[i:i + 3]     if part == 'aaa':         newstr += '1'     elif part == 'aba':         newstr += '2'     elif part == 'abc':         newstr += '3'     elif part == 'cab':         newstr += '4' print newstr

if sequence of 3 characters doesn't anything, there's not point in having check it; quietly continue on next one.

if have heart set on using str.replace replace these strings within code, should @ optional third parameter count. if limit single replacement each loop, should achieve desired result.


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