uk sort code regex with string -

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i have string input uk sort code. (ex: "my uk sort code 873492"). customer types , agent has respond "my uk sort code ******".

forum posts here regex doesn't how mask uk code , leave string is. please help!

thanks!

as sort codes have 6 digits , formatted 3 pairs of numbers (e.g. 12-34-56) try match that, need like:

var sortcode = document.getelementbyid("sortcode");  var result = document.getelementbyid("result");    sortcode.oninput = function(e){       var match = sortcode.value.match(/\d{6}|\d{2}\s*?\-\s*?\d{2}\s*?\-\s*?\d{2}/);         if(match == null)      result.innerhtml = "there no sort code in input";    else      result.innerhtml = sortcode.value.replace(/\d{6}|\d{2}\s*?\-\s*?\d{2}\s*?\-\s*?\d{2}/g, "******")      };
<input type="text" id="sortcode" placeholder="enter sentence sort code"/>    <div id="result"></div>

note match:

  • any formatted sort code if there spaces between digits , dashes (e.g. 12- 34 -56 ******).
  • numbers multiple of 6 number of digits (e.g. 123456789012 ************).
  • any 6 digits number if not space delimited (e.g. 123456789 ******789).

if don't want that, can make assumptions make more restrictive less probable hide not sort code, @ same time more probable not match sort code not match criteria.

for example, let's sort codes preceded space , @ end of sentence (i.e. followed nothing or dot). code be:

var sortcode = document.getelementbyid("sortcode");  var result = document.getelementbyid("result");    sortcode.oninput = function(e){       var match = sortcode.value.match(/\s\d{6}\.?$|\s\d{2}\s*?\-\s*?\d{2}\s*?\-\s*?\d{2}\.?$/);         if(match == null)      result.innerhtml = "there no sort code in input";    else      result.innerhtml = sortcode.value.replace(/\s\d{6}\.?$|\s\d{2}\s*?\-\s*?\d{2}\s*?\-\s*?\d{2}\.?$/, " ******")      };
<input type="text" id="sortcode" placeholder="enter sentence sort code"/>    <div id="result"></div>


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